Personality Quiz
$$\((sqrt{3x}-2)^2)<5\)$$ \(ax^2 + bx + c = 0\) $$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$ $$\sqrt{\left(3x-2\right)^2}\lt 5$$ $$\left(\frac{\sqrt x}{y^3}\right)$$ $$\left\right$$ $$\sqrt 2x + 5 = 3$$ $$x + 2 – \frac {15} {x} = 0$$ $$16 = \frac {k} {11}$$ $$2y = x + 7$$