$$\((sqrt{3x}-2)^2)<5\)$$

\(ax^2 + bx + c = 0\)

$$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$

$$\sqrt{\left(3x-2\right)^2}\lt 5$$

$$\left(\frac{\sqrt x}{y^3}\right)$$

$$\left\right$$

$$\sqrt 2x + 5 = 3$$

$$x + 2 – \frac {15} {x} = 0$$

$$16 = \frac {k} {11}$$

$$2y = x + 7$$

$$\int \left(x\right) = x^2 + 4x + 5$$

$$x = -2$$, or $$x=5$$

/9
18

1 / 9

Category: Odd Words

Solve the inequality: $$\sqrt{\left(3x-2\right)^2}\lt 5$$

2 / 9

Category: Odd Words

Solve the equation: $$-\left(x - 2\right)^2 - 2 = 7$$

3 / 9

Category: Odd Words

$$\left(-x + 3\right)^2 - 12 = 8$$

4 / 9

Category: Odd Words

$a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

5 / 9

Category: Odd Words

Select the odd one

6 / 9

Category: English Vocabulary

$${\frac x5} = 2$$

7 / 9

Category: English Vocabulary

$$\sqrt 2x + 5 = 3$$

8 / 9

Category: English Vocabulary

He’s a waiter; she’s a _________.

9 / 9

Category: English Vocabulary

She’s a police officer, so she has to wear a _________ at work.

The average score is 69%

0%

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